Asked by Domuz Gribi Hayat
Solve the initial value problem 2x2y′′+xy′−3y= 0 wherey(1) = 1,y′(1) = 4.
Answers
Answered by
oobleck
2x^2 y′′+xy′−3y= 0
y = c1 x^(3/2) + c2/x
now plug in the conditions
y = c1 x^(3/2) + c2/x
now plug in the conditions
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.