Asked by RAJ
Solve the initial value problem 3(y-1)^2 = y'', with y(0) = 3 and y'(0) = 4. Assume y does not equal 1.
Answers
Answered by
Steve
You sure there's no typo here? The solution is really a mess:
http://www.wolframalpha.com/input/?i=solve+y%22+%3D+3%28y-1%29^2&a=*C.solve-_*SolveWord-
http://www.wolframalpha.com/input/?i=solve+y%22+%3D+3%28y-1%29^2&a=*C.solve-_*SolveWord-
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