Asked by Misha
Solve the initial value problem: dy/dt-y=7e^t + 10e^6t with y(0)=4
y = ?
y = ?
Answers
Answered by
oobleck
you know that the solution to dy/dt - y = 0 is
y = c e^t
that means that the solution to y'-y=7e^t + 10e^6t is
y = c e^t + 7t e^t + 2e^6t
y = c e^t
that means that the solution to y'-y=7e^t + 10e^6t is
y = c e^t + 7t e^t + 2e^6t
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