Asked by Tania
Solve the initial value problem explicity:
y'= 5xe^(-y), y(1)=1
y'= 5xe^(-y), y(1)=1
Answers
Answered by
MathMate
This equation is separable:
y'/(5e^(-y)) = x
Integrate and substitute y(1)=1 to solve for the integration constant C.
See solution to your other post for reference:
http://www.jiskha.com/display.cgi?id=1296694049
y'/(5e^(-y)) = x
Integrate and substitute y(1)=1 to solve for the integration constant C.
See solution to your other post for reference:
http://www.jiskha.com/display.cgi?id=1296694049
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