Asked by Ashley
A ball thrown upward reaches a height of 13m. How much time did it take to get to this height? How much time will take to fall to the ground?
Answers
Answered by
bobpursley
consider energy.
InitialKineticEnergy=finalPotentialEnergy
1/2 mv^2=mg*13
V =sqrt(2*9.8*13) that is the initial velocity.
the average velocity going up is half that, so time up= 12/(1/2 sqrt(2*9.8*13)
grab your calculator.
Time down is the same as time up.
InitialKineticEnergy=finalPotentialEnergy
1/2 mv^2=mg*13
V =sqrt(2*9.8*13) that is the initial velocity.
the average velocity going up is half that, so time up= 12/(1/2 sqrt(2*9.8*13)
grab your calculator.
Time down is the same as time up.
Answered by
Anonymous
yhtrh
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