a. hf=hi+vi*t-4.9t^2 hi=34 vi=6, t=1
b. vf=vi-9.8t
c. hf=hi+ same as a but now hf=0, solve for t.
A ball is thrown upward with an initial velocity of 6.0m/s by someone on top of the building 34m tall who is leaning over the edge so that the ball will not strike the building on the return trip. (a) How far above the ground will the ball be at the end of 1.0s? (b) What is the ball's velocity at the time? (c) When and with what speed will the ball strike the ground?
1 answer
1 answer