Question
A ball is thrown upward at 20 metres per second off the top of a building that is 12 m high.
What is the height of the ball above the ground at its highest poin?
What is the height of the ball above the ground at its highest poin?
Answers
v = Vi - g t
0 = 20 - 9.81 t at top when v = 0
t = 2.04 seconds
h = 12 + Vi t -(1/2) g t^2
h = 12 + 20(2.04) -4.9(2.04)^2
h = 32.4 meters
0 = 20 - 9.81 t at top when v = 0
t = 2.04 seconds
h = 12 + Vi t -(1/2) g t^2
h = 12 + 20(2.04) -4.9(2.04)^2
h = 32.4 meters
Related Questions
A ball is thrown upward from the ground with an initial speed of 16.0 m/s; at the same instant, anot...
A ball with a mass 0.15kg is thrown upward with an initial velocity 20m/s from the roof of a buildin...
If a ball is thrown upward from ground level with an initial velocity
of 24 m/s, its height h in me...
A ball is thrown upward from the top of a 48-foot-high building. The ball is 64 feet above ground l...