Asked by Nthabiseng
A ball is thrown upward at 20 metres per second off the top of a building that is 12 m high.
What is the height of the ball above the ground at its highest poin?
What is the height of the ball above the ground at its highest poin?
Answers
Answered by
Damon
v = Vi - g t
0 = 20 - 9.81 t at top when v = 0
t = 2.04 seconds
h = 12 + Vi t -(1/2) g t^2
h = 12 + 20(2.04) -4.9(2.04)^2
h = 32.4 meters
0 = 20 - 9.81 t at top when v = 0
t = 2.04 seconds
h = 12 + Vi t -(1/2) g t^2
h = 12 + 20(2.04) -4.9(2.04)^2
h = 32.4 meters
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