Ask a New Question

Question

A ball is thrown upward with velocity 5m/s calculate total distance covered by it ?{
Using formulae (v)2 -(u)2. =2gs}
8 years ago

Answers

Steve
h(t) = 5t - 4.9t^2
max height at t=5/9.8
so, figure h at that value of t.

Total distance is that height up, then back down.
8 years ago

Related Questions

A ball is thrown upward with an initial velocity of 96 feet per second from the top of a 100 foot bu... A ball thrown upward at 60.0 m/s has what speed after 5 seconds? What equation do I use? When a ball is thrown upward, its height, h, in metres, is given by h=1.5 +19.6t -4.9t², where t is... A ball is thrown upward with an initial velocity of 6.0m/s by someone on top of the building 34m tal... A ball is thrown upward in such a way that its speed is 32.3 m/s when it is at half its maximum heig... A ball is thrown upward. What is its time interval between the release of he ball and the time it re... A ball thrown upward from the a point 7 meters below the bottom of a window rises past the window, w... A ball is thrown upward with an initial velocity of 4 ft/sec from a height of 10 feet. What is the m... a 0.5 kg ball is thrown upward with an iniatial speed of 10 m/s, what is the initial kinetic energy... a ball thrown upward with a velocity of 19.6m/s will come momentarily in rest in? Ans 2sec
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use