Asked by Isabella Salandini
A ball is thrown upward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, how high above the ground is the ball at the following times?
(a) 0.90 s after it is thrown
(b) 2.10 s after it is thrown
(a) 0.90 s after it is thrown
(b) 2.10 s after it is thrown
Answers
Answered by
R_scott
h = -5 t^2 + 14 t ... meters
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