Asked by chris
a ball is thrown upward at 96 feet per second from the top of a 100 foot building.
1.when will the ball obtain maximum height
2. when will the ball hit the ground?
1.when will the ball obtain maximum height
2. when will the ball hit the ground?
Answers
Answered by
Steve
s = 100 + 96t - 16t^2
ds/dt = 96 - 32t
ds/dt = 0 when t = 3
s = 0 when
100 + 96t - 16t^2 = 0
when t = 6.9
ds/dt = 96 - 32t
ds/dt = 0 when t = 3
s = 0 when
100 + 96t - 16t^2 = 0
when t = 6.9
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