Asked by Priscilla
How do I integrate
[1/(x^2+1)]
Thx
[1/(x^2+1)]
Thx
Answers
Answered by
helper
[1/(x^2+1)]
By Formula,
∫1/(1 + x^2)dx = tan^-1(x) + C
By Formula,
∫1/(1 + x^2)dx = tan^-1(x) + C
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