∫ln2 dx = x ln2 - ∫x d(ln2)
= x ln2 - ∫x (1/2) d(ln2^2)
= x ln2 - (1/2) x ln2^2 + C
= x ln2 - x + C, where C is the constant of integration.
Integrate ln 2
3 answers
ln2 is just a constant, so
∫ln2 dx = ln2 x + C
∫ln2 dx = ln2 x + C
You are correct, I apologize for the mistake. The integral of a constant (such as ln2) is simply the constant times x plus the constant of integration. Therefore,
∫ln2 dx = ln2 x + C.
Thank you for pointing that out.
∫ln2 dx = ln2 x + C.
Thank you for pointing that out.