Write as a single log : 3log2+2log8- 1/2 log4 ( simplify your answer)
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3log2+2log8- 1/2 log4
= log (2^3) + log(8^2) - log(4^(1/2))
= log 8 + log 64 - log 2
= log(8*64/2)
= log 256
= log (2^3) + log(8^2) - log(4^(1/2))
= log 8 + log 64 - log 2
= log(8*64/2)
= log 256
On the second line of this equation how did you get = log 8 + log 64 - log 2
1 answer