Question
write as a single log
log(underscore3)(3x-6)-[log(underscore3)(x^2-4)+log(underscore3)81]
thanks
log(underscore3)(3x-6)-[log(underscore3)(x^2-4)+log(underscore3)81]
thanks
Answers
Reiny
according to your basic laws of logs your expression is
log<sub>3</sub> ((3x-6)(x^2 - 4)/81)
log<sub>3</sub> ((3x-6)(x^2 - 4)/81)
Reiny
I misread you + and - signs
should be
log<sub>3</sub> (81(3x-6)/(x^2 - 4))
should be
log<sub>3</sub> (81(3x-6)/(x^2 - 4))
Reiny
which reduces to
log<sub>3</sub> 243/(x-2) , x > 2
log<sub>3</sub> 243/(x-2) , x > 2
Deb
Thank you