write as a single log

Question

log(underscore3)(3x-6)-[log(underscore3)(x^2-4)+log(underscore3)81]

thanks

Answer 1

according to your basic laws of logs your expression is

log₃ ((3x-6)(x^2 - 4)/81)

Answer 2

I misread you + and - signs

should be

log₃ (81(3x-6)/(x^2 - 4))

Answer 3

which reduces to

log₃ 243/(x-2) , x > 2

Answer 4

Thank you