Asked by Deb

write as a single log

log(underscore3)(3x-6)-[log(underscore3)(x^2-4)+log(underscore3)81]

thanks
Answered by Reiny
according to your basic laws of logs your expression is

log<sub>3</sub> ((3x-6)(x^2 - 4)/81)
Answered by Reiny
I misread you + and - signs

should be

log<sub>3</sub> (81(3x-6)/(x^2 - 4))
Answered by Reiny
which reduces to

log<sub>3</sub> 243/(x-2) , x > 2
Answered by Deb
Thank you
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