Asked by loren
write 5-log2(4y) as a single quantity
Answers
Answered by
Reiny
assuming log2 (4y) means log<sub>2</sub> (4y)
I could write 5 as log<sub>2</sub> 32
so we have:
5 - log<sub>2</sub> (4y)
= log<sub>2</sub> 32 - log<sub>2</sub> (4y)
= log<sub>2</sub> (32/(4y))
= log<sub>2</sub> (8/y)
I could write 5 as log<sub>2</sub> 32
so we have:
5 - log<sub>2</sub> (4y)
= log<sub>2</sub> 32 - log<sub>2</sub> (4y)
= log<sub>2</sub> (32/(4y))
= log<sub>2</sub> (8/y)
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