Ka is not needed.
mL x M = mL x M.
What volume of 0.115M NaOH is required to reach the equivalence point in the titration of 25.00 mL of 0.200M of HF?
Ka(HF)=7.4 x 10^-4
1 answer
Ka(HF)=7.4 x 10^-4
1 answer
2 answers
1 answer
1 answer
0 answers