Asked by Jesse
A baseball is released at rest from the top of the washington Monument. It hits the ground after falling for 6.0 s. What was the height from which the ball was dropped? (g=9.8 m/s2 and assume air resistance is negligible)
Answers
Answered by
bobpursley
h=1/2 g t^2
Answered by
drwls
The distance it falls in time t is
Y = (1/2) g t^2.
That is a formula you need to learn.
Apply it.
Y = (1/2) g t^2.
That is a formula you need to learn.
Apply it.
Answered by
Love Maltiby
y = (1/2)(-9.80 m/s2)(6.0s)^2
y = (-4.9 m/s2)(36.0s2)
y = 176.4 m
y = (-4.9 m/s2)(36.0s2)
y = 176.4 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.