Asked by Jane
An object is released from rest. How far does it fall during the third second of its fall?
Answers
Answered by
bobpursley
find the d istance fell at end of third, and subtract the distance at the end of second.
d= d(3)-d(2)=1/2 g (3^2-2^2)
check that.
d= d(3)-d(2)=1/2 g (3^2-2^2)
check that.
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