Ask a New Question

Question

5-kg box is released from rest on a frictionless incline has a uniform acceleration of 0.24 m/s2, what is the velocity of the box after 4 seconds?
4 years ago

Answers

Anonymous
v = a t = 0.24 * 4
The rest is just there to confuse you.
4 years ago

Related Questions

The block is released from rest on the frictionless ramp. It compresses the spring by 20cm before m... An object is released from rest at height h above the surface of the Earth, where h is much smaller... An object is released from rest on a planet that has no atmosphere. The object falls freely for 5.02... If it is released from rest at a height of h = 2 ft from the top of the uncompressed spring, determi... A car is released from rest on a frictionless inclined plane. (Figure: twitpic com/e8nkhj) Calculate... A rock is released from rest on a 700 m building and time is 11.95 what is the speed and velocity of... A block is released from rest at point A and slides down a curved slope to point B, then continues... A block is released from rest on an inclined plane and moves 3.5 m during the next 3.5 s. The acce... A block is released from rest on an inclined plane and moves 3.1 m during the next 4.2 s. The acce... A box is released from rest and slides down a ramp in a closed system. Even though the box speeds up...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use