Asked by Jon
What volume of NaOH is required to neutralize 50mL of 0.5M phenol?
So this is just a small calculation in a complex problem, and I would just like someone to check my work so I don't mess up the entire problem based on this calculation.
So mol phenol= molarity x volume
= (0.5mol/L) (0.05 L)
= 0.025mol
phenol and NaOH are a 1:1 molar ratio sooo
V NaOH= 0.025mol/ (2 mol/L)
= 0.0125 L
= 12.5mL
Therefore, 12.5mL of NaOH is required to neutralize 50mL of 0.5M phenol.
Is this correct? I think the part that I'm most uncertain about is the 1:1 molar ratio.
So this is just a small calculation in a complex problem, and I would just like someone to check my work so I don't mess up the entire problem based on this calculation.
So mol phenol= molarity x volume
= (0.5mol/L) (0.05 L)
= 0.025mol
phenol and NaOH are a 1:1 molar ratio sooo
V NaOH= 0.025mol/ (2 mol/L)
= 0.0125 L
= 12.5mL
Therefore, 12.5mL of NaOH is required to neutralize 50mL of 0.5M phenol.
Is this correct? I think the part that I'm most uncertain about is the 1:1 molar ratio.
Answers
Answered by
DrBob222
Your question doesn't state the concn of the NaOH. If it is 2.00 M, the calculation is correct. The neutralization between phenol and NaOH is, indeed, 1:1.
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