Asked by Anonymous
Find moles of NaOH required(used) to react with CH3COOH.
The volume of NaOH used was 7.70mL and the actual molarity of NaOH solution is .275 mol/L.
The volume of NaOH used was 7.70mL and the actual molarity of NaOH solution is .275 mol/L.
Answers
Answered by
oobleck
you don't say how much CH3COOH is involved.
So who knows how much NaOH will be needed?
But, the amount of NaOH present is
7.70mL * 1L/1000mL * 0.275 mol/L = 0.00212 mol
So who knows how much NaOH will be needed?
But, the amount of NaOH present is
7.70mL * 1L/1000mL * 0.275 mol/L = 0.00212 mol
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