Asked by Nasir
What volume of a 0.500 M NaOH solution is needed to neutralize 60.0 mL of 0.15 M HCl solution?
Answers
Answered by
DrBob222
mols HCl = M x L = ?
mols NaOH = mols HCl (look at tahe coefficients; the rxn is 1:1).
Then M NaOH = mols NaOH/L NaOH.
mols NaOH = mols HCl (look at tahe coefficients; the rxn is 1:1).
Then M NaOH = mols NaOH/L NaOH.
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