Ask a New Question

Question

Wrtie the equilibrium constant expression for the reaction of NH3 with water. the OH- concentration of .050 M ammonia, NH3, is 9.5 x 10^-4 M
14 years ago

Answers

DrBob222
NH3(aq) ==> NH4^+ + OH^-

K = (NH4^+)(OH^-)/(NH3)
This is the expression; I don't know what the numerical values mean.
14 years ago

Related Questions

Given the equilibrium constant values: 1.N2(g)+ 1/2O2(g)<---> N2O(g) KC=2.7*10^{-18} 2.N2O4(... An equilibrium constant ... A. is independent of temperature. B. is small when the products ar... The equilibrium constant (Kc) for the gas phase reaction 2 NH3 N2 + 3 H2 is 3.0 x 10-3 at some temp... The equilibrium constant for the reaction 2NO(g) + O2(g) <--> 2NO2(g) is Kp=1.48x10^4 at 184C. Calc... Given the equilibrium constant values: N2 + 1/2O2 >>> N2O ; kc = 2.7 * 10^-18 N2O4>>>>2NO2 kc=... The equilibrium constant kc for the reaction N2(g)+ 3H(g)---2NH3(g) at 450C is 0.159. Calculate th... The equilibrium constant kc for the equation CS2 + 4H2 <--> CH4 +2H2S at 900 C is 27.8. what is t... The equilibrium constant (Keq) is the ratio of ____ concentrations to ____ concentrations at equilib... The equilibrium constant for the following reaction is 5.0 at 100c. If an equilibrium mixture contai... If the equilibrium constant K equals .05, and the reaction C3H8=C3H6 + H2 (all gases), starts with p...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use