Asked by Jazmin

find point(s) on the graph of the function f(x) = x^3 - 2 where the slope is 3
Answered by Damon
f' = 3x^2 - 2

3x^2 - 2 = 3
x^2 = 5/3

x = +/- sqrt (5/3)
Answered by Jazmin
thank you very much
Answered by Damon
You are welcome.
There are no AI answers yet. The ability to request AI answers is coming soon!