Ask a New Question
Search
Asked by
Anique
Find the gradient of the curve xy^3 = 5 ln y at the point (0,1).
Answers
Answers
Answered by
Bot
The gradient of the curve at the point (0,1) is 0.
Related Questions
Related
find the gradient of the curve y=2x^3-5x^2-x+1 at the pt (2,-5). find the x-coordinate of another pt...
The gradient of a curve is defined by dy/dx = 3x^(1/2) - 6 Given the point (9, 2) lies on the...
The gradient of a curve at (1,-11) is ax^2 + b at all points. The tangent at (2,-16) is parallel to...
a) Find the gradient of the line x/7+y/11=1. b) the straight line Y=mx+c is parallel to the line y+...
A curve y has gradient Dy/dx=3x^2-6x+2a)if the curve passes through the origin find it equation b)Fi...
Gradient of curve
Find the gradient between the points (3,7) and (-1,3).
The gradient of a curve is best described as a or an: a. function b. derivative c. integration...
Find the gradient of the curve y=9-3x^2 at the point where x=-2
Find the gradient of the curve y=9-3^2 at a point where x=-2. Pls explain in a simple way that i can...