Asked by James
The gradient of a curve is defined by
dy/dx = 3x^(1/2) - 6
Given the point (9, 2) lies on the curve, find the equation of the curve
dy/dx = 3x^(1/2) - 6
Given the point (9, 2) lies on the curve, find the equation of the curve
Answers
Answered by
Steve
y' = 3x^(1/2) - 6
y = 2x^(3/2) - 6x + C
y(9) = 2, so
2*27 - 6*9 + C = 2
C = 2
y = 2x^(3/2) - 6x + 2
y = 2x^(3/2) - 6x + C
y(9) = 2, so
2*27 - 6*9 + C = 2
C = 2
y = 2x^(3/2) - 6x + 2
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