Asked by Audrey
How many grams of potassium formate, KHCOO, must be added to 500 mL of a .07 M solution of HCOOH to produce a buffer solution with a pH of 3.50?
given: Ka of HCOOH=1.8 x 10^-4
given: Ka of HCOOH=1.8 x 10^-4
Answers
Answered by
DrBob222
Use the Henderson-Hasselbalch equation and solve for (base)/(acid) concns. Calculate moles acid in the problem, substitute into the B/A ratio and solve for base concn. Then g = moles x molar mass for HCOOK grams.
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