Asked by Blake
How many grams of potassium iodide, KI, are required to make 2.0 L of a 0.1M solution?
Answers
Answered by
Anonymous
Molarity = moles/ Liters
You are given the Molarity (0.1M) and Liters (2.0L). So, plug those into the formula and solve for moles.
0.1M = moles/ 2.0L
moles = 0.2mol
The molecular weight of KI is 166.0028. Convert moles to grams.
0.2mol* (166.0028g/1mol) = 3.2g KI
You are given the Molarity (0.1M) and Liters (2.0L). So, plug those into the formula and solve for moles.
0.1M = moles/ 2.0L
moles = 0.2mol
The molecular weight of KI is 166.0028. Convert moles to grams.
0.2mol* (166.0028g/1mol) = 3.2g KI