Asked by Jo

How many grams of potassium nitrate (KNO3) are required to produce 536 g of potassium nitrite (KNO2) according to the equation below?

*I've tried this question for so long and I get so many different answers in the end so please help.
Answered by Jo
I forgot to add the equation so here it is:
2KNO3(s) ---> 2KNO2(s) + O2(g)
Answered by bobpursley
The mole ratio is 1:1, so figure the moles of potasium nutrite in 536g.

Then figure the number of grams in that same number of moles of postassium nitrate.

Answered by Jo
Moles of potassium nitrite (in 536g) would be 6.29 or 6.3 moles, correct?
Answered by DrBob222
Yes but I would keep the 6.29 since the 536 allows for three significant figures. Don't throw numbers away unless it's necessary.
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