Asked by Anonymous
. How many grams of potassium chloride, KCl, are needed to prepare 0.630 L of a 2.50 M solution of potassium chloride? (4.0 points) (Points :4)
1.575 M
117 g
2.54 m
23.19 g
1.575 M
117 g
2.54 m
23.19 g
Answers
Answered by
vishal
solve by
molarity =no. of moles divide by volume in litres.......
so let the mass be in x grms...
then :
2.50*0.630=x grms
so,
x grms of KCl =1.575 grams is the answer
molarity =no. of moles divide by volume in litres.......
so let the mass be in x grms...
then :
2.50*0.630=x grms
so,
x grms of KCl =1.575 grams is the answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.