Asked by sam
a 20 kg loudspeaker is suspended 2m below a ceiling by two 3m-long cables that angle outward at equal angles. what is the tension in the cables?
Answers
Answered by
bobpursley
The amount of angle is important.
Use symettry, each cable is holding half the weight.
measuring the angle between the vertical and the cable, then 1/2 mg=Tension*cosTheta where theta is from the vertical to a cable.
Use symettry, each cable is holding half the weight.
measuring the angle between the vertical and the cable, then 1/2 mg=Tension*cosTheta where theta is from the vertical to a cable.
Answered by
sam
i got the answer by
(2m/3m)=0.666
sin-1(0.666)=41.8 degrees
to find tension
T=Fg/2sin(theta)
20kg*9.8=196N
2sin(41.8)=1.333
196N/1.3333=147N
(2m/3m)=0.666
sin-1(0.666)=41.8 degrees
to find tension
T=Fg/2sin(theta)
20kg*9.8=196N
2sin(41.8)=1.333
196N/1.3333=147N
Answered by
hoy
jkj;l
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