Asked by Anonymous
A 14-Ω loudspeaker, a 9.0-Ω loudspeaker, and a 3.2-Ω loudspeaker are connected in parallel across the terminals of an amplifier. Determine the equivalent resistance of the three speakers, assuming that they all behave as resistors.
Answer: (1/14)+(1/9)+(1/3.2) = (1/X)
Answer: (1/14)+(1/9)+(1/3.2) = (1/X)
Answers
Answered by
Damon
correct
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