Asked by Destructive interference
Assume you have two loudspeakers separated 1 meter excited by the same oscillator emitting an 1150 Hz sound frequency. You are 4 m from one of the loudspeakers. At what distance from you should be the second loudspeaker to produce destructive interference? Assume the air velocity is 343 m/s.
Answers
Answered by
bobpursley
determine how many wavelengths is 4m.
Then add one half wavelength, convert that to meters. That is the answer.
Then add one half wavelength, convert that to meters. That is the answer.
Answered by
ray matthews
so what's the answer??
Answered by
solution
Lambda = wave length, we get this by velocity / frequency (v/f)
The destructive interefrence is a point were both sound waves cancel's each other out, basically that happens when both speaker have the same oscillator, what they have, and the lambda is moved a half.
Labda = 0.3 and we know that we stay 4m away, so ad the half lambda to 4m or subtrahaet it. = 4.15m or 3.85m
Corre
The destructive interefrence is a point were both sound waves cancel's each other out, basically that happens when both speaker have the same oscillator, what they have, and the lambda is moved a half.
Labda = 0.3 and we know that we stay 4m away, so ad the half lambda to 4m or subtrahaet it. = 4.15m or 3.85m
Corre
Answered by
solution
* maybe it isn't correct, so if someone has the same result pls write, and about the substrate i'm not sure if this works
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