Question

Assume you have two loudspeakers separated 1 meter excited by the same oscillator emitting an 1150 Hz sound frequency. You are 4 m from one of the loudspeakers. At what distance from you should be the second loudspeaker to produce destructive interference? Assume the air velocity is 343 m/s.
bobpursley
determine how many wavelengths is 4m.
Then add one half wavelength, convert that to meters. That is the answer.
so what's the answer??
Lambda = wave length, we get this by velocity / frequency (v/f)
The destructive interefrence is a point were both sound waves cancel's each other out, basically that happens when both speaker have the same oscillator, what they have, and the lambda is moved a half.
Labda = 0.3 and we know that we stay 4m away, so ad the half lambda to 4m or subtrahaet it. = 4.15m or 3.85m

Corre
* maybe it isn't correct, so if someone has the same result pls write, and about the substrate i'm not sure if this works

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