Asked by Megan
An office window has dimensions 3.6 m by 2.5 m. As a result of the passage of a storm, the outside air pressure drops to 0.925 atm, but inside the pressure is held at 1.0 atm. What net force pushes out on the window?
Answers
Answered by
MathMate
That's a big panoramic window!
1 atmospheric pressure is 101,325 pascals
=101,325 N/m²
The difference in pressure, ΔP
= (1-0.925)atm
= 0.075*101325 pascals
= 7599 Pa
Area of the window
A = 3.6*2.5 m²
Outward force
= ΔP*A
1 atmospheric pressure is 101,325 pascals
=101,325 N/m²
The difference in pressure, ΔP
= (1-0.925)atm
= 0.075*101325 pascals
= 7599 Pa
Area of the window
A = 3.6*2.5 m²
Outward force
= ΔP*A
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