Asked by alec
From a window 20m above the ground, a person could see the top of the house across the street at an angle of elevation of 5 degrees. The angle of depression to the base of the house was 15 degrees. What is the height of the house?
Answers
Answered by
Reiny
I will assume you made a sketch.
On mine, I let the top of the house across the street be P and its bottom Q.
I let the point directly across the window (W) be R
We know QR = 20
tan15° = 20/WR
WR = 20/tan15
In the other triangle,
tan5° = PR/WR
PR = WRtan5 = (20/tan15)(tan5)
= ...
height = 20 + PR
= ...
take over
On mine, I let the top of the house across the street be P and its bottom Q.
I let the point directly across the window (W) be R
We know QR = 20
tan15° = 20/WR
WR = 20/tan15
In the other triangle,
tan5° = PR/WR
PR = WRtan5 = (20/tan15)(tan5)
= ...
height = 20 + PR
= ...
take over
Answered by
Anonymous
From a window 20m above the ground, a person could see the top of the house across the street at an angle of elevation of 5 degrees. The angle of depression to the base of the house was 15 degrees. What is the height of the house?
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