Question
what is the vertex and axis of symmetry
y=2x^2 - 7x + 1
y=2x^2 - 7x + 1
Answers
Henry
Y = 2x^2 - 7x + 1.
V(h , k),
h = Xv = -b / 2a,
= 7 / 4 = 1 3/4.
Substitute 7/4 for x in the given Eq:
k = Yv = 2(7/4)^2 - 7(7/4) +1,
= 98/16 - 49/4 +1,
= 49/8 - 49/4 + 8/8,
= 49/8 - 98/8 + 8/8,
= - 41/8 = -5 1/8.
V(1 3/4 , - 5 1/8).
Axis of Sym. = h = Xv = 1 3/4.
V(h , k),
h = Xv = -b / 2a,
= 7 / 4 = 1 3/4.
Substitute 7/4 for x in the given Eq:
k = Yv = 2(7/4)^2 - 7(7/4) +1,
= 98/16 - 49/4 +1,
= 49/8 - 49/4 + 8/8,
= 49/8 - 98/8 + 8/8,
= - 41/8 = -5 1/8.
V(1 3/4 , - 5 1/8).
Axis of Sym. = h = Xv = 1 3/4.