Asked by luke

what is the vertex and axis of symmetry

y=2x^2 - 7x + 1

Answers

Answered by Henry
Y = 2x^2 - 7x + 1.

V(h , k),
h = Xv = -b / 2a,
= 7 / 4 = 1 3/4.

Substitute 7/4 for x in the given Eq:
k = Yv = 2(7/4)^2 - 7(7/4) +1,
= 98/16 - 49/4 +1,
= 49/8 - 49/4 + 8/8,
= 49/8 - 98/8 + 8/8,

= - 41/8 = -5 1/8.

V(1 3/4 , - 5 1/8).

Axis of Sym. = h = Xv = 1 3/4.


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