Question

Identify the vertex, axis of symmetry, and direction of opening for y=2(x+3)^2-5.

vertex = 1/2
axis = 1/2
direction = up

Answer 1

your text should have the following:

for y = a(x-p)^2 + q

vertex is (p,q)
axis of symmetry: x=p
opening: up if a>0, down if a<0

please redo your answers and let me know what you got.

Answer 2

y=2x+3^2-5
y=2x+9-5

x=-b/2a
x=-9/2(-9)
x=1/2

I don't know if I have the value for a right

Answer 3

vertex= (3,-5)
axis of symmetry= x=2
direction= up b/c 2>0