a 65kg diver jumps off of a 10m tower. find the diver´s velocity when he hits the water?

Answer 1

Set potential energy equal to potential energy. i.e. mgh = (1/2)mv^2

where m=mass, g=gravity or 9.8m/s^2, h=height, v=velocity

In the beginning, the diver has potential energy (since the person is raised at a certain distance above ground level). As the diver falls, this distance decreases and the velocity picks up - thus kinetic energy accumulates.

Although one form of energy is transformed in another form of energy, energy is conserved throughout the process.