Asked by donna
a sky diver jumps out of a plane at a height of 5000 ft. if her parachute does not open until she reaches 1000 ft, what is her velocity at that point if air resisitance is disreguared?
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*d
V^2 = 0 + 64*(5000-1000) = 256,000
V = 506 Ft/s
V^2 = 0 + 64*(5000-1000) = 256,000
V = 506 Ft/s
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