Asked by danaja
a diver of mass 101 kg jumps upward off a diving board into water. Diving board is 6m above water. Driver has a speed of 1.2m/s. based on speed how high above the board will she rise?
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h
V = 0
Vo = 1.2 m/s
g = -9.8 m/s^2
h = ?
V = 0
Vo = 1.2 m/s
g = -9.8 m/s^2
h = ?
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