Asked by liz
Find the intersection of the line through (0, 1) and (4.4, 2) and the line through (1.9, 3) and (5.3, 0). (Round your answers to the nearest tenth.)
(x, y) =
(x, y) =
Answers
Answered by
Henry
(0 , 1) , (4.4 , 2).(1.9 , 3)(5.3 , 0).
m1 = (2 - 1) / (4.4 - 0)
= 1 / 4.4 = 0.227,
y = mx + b,
1 = 0.227*0 + b,
b = 1.
Eq1. y = 0.227x + 1.
(1.9 , 3) , (5.3 , 0),
m2 = (0 - 3) / (5,3 - 1.9),
= -3 / 3.4 = -0.88,
y = mx + b,
3 = -0.88*1.9 + b,
3 = -1.68 + b,
3 + 1.68 = b,
b = 4.68.
Eq2. y = -0.88x + 4.68.
Substitute Eq1 for y in Eq2:
0.227x + 1 = -0.88x + 4.68,
0.227x + 0.88x = 4.68 - 1,
1.107x = 3.68,
x = 3.68 /1.107 = 3.32.
Substitute 3.32 for x in Eq1:
y = 0.227*3.32 + 1,
= 0.755 + 1,
= 1.76.
Solution set: (x , y) = (3.3 , 1.8) =
Point where the 2 lines intersect.
m1 = (2 - 1) / (4.4 - 0)
= 1 / 4.4 = 0.227,
y = mx + b,
1 = 0.227*0 + b,
b = 1.
Eq1. y = 0.227x + 1.
(1.9 , 3) , (5.3 , 0),
m2 = (0 - 3) / (5,3 - 1.9),
= -3 / 3.4 = -0.88,
y = mx + b,
3 = -0.88*1.9 + b,
3 = -1.68 + b,
3 + 1.68 = b,
b = 4.68.
Eq2. y = -0.88x + 4.68.
Substitute Eq1 for y in Eq2:
0.227x + 1 = -0.88x + 4.68,
0.227x + 0.88x = 4.68 - 1,
1.107x = 3.68,
x = 3.68 /1.107 = 3.32.
Substitute 3.32 for x in Eq1:
y = 0.227*3.32 + 1,
= 0.755 + 1,
= 1.76.
Solution set: (x , y) = (3.3 , 1.8) =
Point where the 2 lines intersect.
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