Asked by Anonymous
Find the intersection of the line in three dimensions whose equation is x/2 = (y-1)/3 = z/4
and the plane x + 2y + 3z = 5.
and the plane x + 2y + 3z = 5.
Answers
Answered by
Reiny
the parametric equations for x/2 = (y-1)/3 = z/4 .....
x = 0 + 2t
y = 1 + 3t
z = 0 + 4t
sub into the plane equation:
0+2t + 2(1+3t) + 3(0+4t) = 5
find t, then sub into the parametric equations to find (x,y,z)
x = 0 + 2t
y = 1 + 3t
z = 0 + 4t
sub into the plane equation:
0+2t + 2(1+3t) + 3(0+4t) = 5
find t, then sub into the parametric equations to find (x,y,z)