Asked by Anonymous
                Find the intersection of the line in three dimensions whose equation is   x/2 = (y-1)/3 = z/4
and the plane x + 2y + 3z = 5.
            
        and the plane x + 2y + 3z = 5.
Answers
                    Answered by
            Reiny
            
    the parametric equations for x/2 = (y-1)/3 = z/4 .....
x = 0 + 2t
y = 1 + 3t
z = 0 + 4t
sub into the plane equation:
0+2t + 2(1+3t) + 3(0+4t) = 5
find t, then sub into the parametric equations to find (x,y,z)
    
x = 0 + 2t
y = 1 + 3t
z = 0 + 4t
sub into the plane equation:
0+2t + 2(1+3t) + 3(0+4t) = 5
find t, then sub into the parametric equations to find (x,y,z)
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