Asked by Joy
Find the intersection of two lines. i have the answer just please tell me how it was made
4x-3y-4=0 , 4x+2y+5=0
-5y/-5 = 9/-5
y= 9/5
4x-3(-9/5)-4=0
5(4x+27/5-4=0)
20x+27-20=0
20x+7=0
20x/20=-7/20
x=-7/20
(-7/20, -9/5
4x-3y-4=0 , 4x+2y+5=0
-5y/-5 = 9/-5
y= 9/5
4x-3(-9/5)-4=0
5(4x+27/5-4=0)
20x+27-20=0
20x+7=0
20x/20=-7/20
x=-7/20
(-7/20, -9/5
Answers
Answered by
Steve
If you subtract the 2nd equation from the first, you get
4x-3y-4 = 0
4x+2y+5 = 0
----------------
-5y-9 = 0
now add 9 to both sides:
-5y = 9
now divide by -5:
y = -9/5
Knowing that y = -9/5, just plug it into either of the original equations and then solve for x. The work is shown above. If you have trouble following the steps in logic, you need to do a bunch of these on your own.
4x-3y-4 = 0
4x+2y+5 = 0
----------------
-5y-9 = 0
now add 9 to both sides:
-5y = 9
now divide by -5:
y = -9/5
Knowing that y = -9/5, just plug it into either of the original equations and then solve for x. The work is shown above. If you have trouble following the steps in logic, you need to do a bunch of these on your own.