Question
rry leaves home at 4:07 and runs at a constant speed to the lamppost. He reaches the lamppost at 4:11, immediately turns, and runs to the tree. Larry arrives at the tree at 4:22. What is Larry's average velocity during his entire trip, if the lamppost is 363.0 m west of home, and the tree is 699.0 m east of home?
Answers
bobpursley
avg velocity= distancetraveled/time
Do you have questions about how to compute this?
Do you have questions about how to compute this?
Ash
No..so is it 363+699+363 / 240s + 660s ?