Asked by Anonymous
A girl leaves her home A at 9am, and after cycling for 25km at 5km/h she reaches her destination B at 2pm. After having lunch at B for 90 minutes, she sets off for home. On the way home she stops for half an hour to see a friend who lives at C, which is 10km from A. At 5:30pm, she leaves C and cycles until she reaches home at 7pm.
a) What was the girls speed from B to C?
b) What was her speed from C to home?
a) What was the girls speed from B to C?
b) What was her speed from C to home?
Answers
Answered by
Steve
what's the problem? Just calculate the distance and time as needed, and the average speed is distance/time.
For (a),
A-B is 25km
A-C is 10km
So, B-C is 15km
C-A takes 1.5 hr
B-A takes 3.5 hr
stop at C takes 0.5 hr
So, the B-C leg takes 1.5 hr
15km/1.5hr = 10km/hr
The rest is now easy, given the above data.
For (a),
A-B is 25km
A-C is 10km
So, B-C is 15km
C-A takes 1.5 hr
B-A takes 3.5 hr
stop at C takes 0.5 hr
So, the B-C leg takes 1.5 hr
15km/1.5hr = 10km/hr
The rest is now easy, given the above data.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.