Asked by George Carl
A person leaves her home and walks 6 miles due east and then 4 miles southeast?How far away from home is she?What is her net displacement(determine the magnitude and direction of the displacement vector)?
Answers
Answered by
scott
east ... 6 + 2√2
south ... 2√2
use Pythagoras to find the distance
the direction angle is in Quad IV ... tan(Θ) = south / east
south ... 2√2
use Pythagoras to find the distance
the direction angle is in Quad IV ... tan(Θ) = south / east
Answered by
Reiny
D^2 = 6^2 + 4^2 = 52
D = 2√13 or appr 7.2 units from home
angle:
as Scott said, tanØ = 4/6
Ø = appr 33.7°
depending on your notation, direction angle = -33.7°
or bearing of 123.7°
or E 33.7° S
D = 2√13 or appr 7.2 units from home
angle:
as Scott said, tanØ = 4/6
Ø = appr 33.7°
depending on your notation, direction angle = -33.7°
or bearing of 123.7°
or E 33.7° S
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