Asked by kurt
                C leaves home going 40 km/h. when c is 9 km from home, d starts after c from the same place, going 58 km/h. how long does it take d to catch up to c?
            
            
        Answers
                    Answered by
            Damon
            
    time c goes alone = 9/40
time d goes = (t -9/40)
distances are the same so
40 t = 58 (t - 9/40)
    
time d goes = (t -9/40)
distances are the same so
40 t = 58 (t - 9/40)
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