Asked by kurt
C leaves home going 40 km/h. when c is 9 km from home, d starts after c from the same place, going 58 km/h. how long does it take d to catch up to c?
Answers
Answered by
Damon
time c goes alone = 9/40
time d goes = (t -9/40)
distances are the same so
40 t = 58 (t - 9/40)
time d goes = (t -9/40)
distances are the same so
40 t = 58 (t - 9/40)
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