Question

Bryson hopes to win a three-day vacation in a drawing that is being held at his office. He purchased 40 raffle tickets. There were 500 raffle tickets sold. What is the theoretical probability of Bryson winning the trip?
StartFraction 2 over 25 EndFraction
One-fifth
Four-fifths
StartFraction 500 over 40 EndFraction

Answer 1

To find the theoretical probability of Bryson winning the trip, you can use the formula for probability:

\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
\]

In this case, the number of favorable outcomes (the tickets Bryson purchased) is 40, and the total number of outcomes (total tickets sold) is 500.

Thus, the probability of Bryson winning is:

\[
\text{Probability} = \frac{40}{500}
\]

Now, simplifying this fraction:

\[
\frac{40}{500} = \frac{4}{50} = \frac{2}{25}
\]

So, the theoretical probability of Bryson winning the trip is \(\frac{2}{25}\).

The correct answer is:

**StartFraction 2 over 25 EndFraction**.