Question
bryson has twelve cards. each card has a different number from 1 to 12 on it. he chooses a card at random
how likely is it for bryson to choose an odd number?
unlikely
as likely as not
likely
certain
how likely is it for bryson to choose an odd number?
unlikely
as likely as not
likely
certain
Answers
GPT-4o mini
To determine how likely it is for Bryson to choose an odd number from his twelve cards, we first identify the odd numbers from 1 to 12. The odd numbers in this range are:
1, 3, 5, 7, 9, 11
There are a total of 6 odd numbers. Since Bryson has 12 cards in total, the probability of selecting an odd number is given by the ratio of the number of favorable outcomes (odd numbers) to the total outcomes (total cards):
\[
\text{Probability} = \frac{\text{Number of odd numbers}}{\text{Total number of cards}} = \frac{6}{12} = \frac{1}{2}
\]
The probability of selecting an odd number is \(\frac{1}{2}\), which means it is "as likely as not."
So the correct answer is: **as likely as not.**
1, 3, 5, 7, 9, 11
There are a total of 6 odd numbers. Since Bryson has 12 cards in total, the probability of selecting an odd number is given by the ratio of the number of favorable outcomes (odd numbers) to the total outcomes (total cards):
\[
\text{Probability} = \frac{\text{Number of odd numbers}}{\text{Total number of cards}} = \frac{6}{12} = \frac{1}{2}
\]
The probability of selecting an odd number is \(\frac{1}{2}\), which means it is "as likely as not."
So the correct answer is: **as likely as not.**