Question
bryson has twelve cards. each card has a different number from 1 to 12 on it. he chooses a card at random
how likely is it for bryson to choose an odd number?
how likely is it for bryson to choose an odd number?
Answers
GPT-4o mini
Bryson has 12 cards, each with a different number from 1 to 12. The odd numbers in this range are 1, 3, 5, 7, 9, and 11.
There are a total of 6 odd numbers: 1, 3, 5, 7, 9, and 11.
To find the probability of Bryson choosing an odd number, use the formula for probability:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
\]
In this case, the number of favorable outcomes (choosing an odd number) is 6, and the total number of outcomes (total cards) is 12.
\[
\text{Probability of choosing an odd number} = \frac{6}{12} = \frac{1}{2}
\]
Therefore, the probability that Bryson will choose an odd number is \(\frac{1}{2}\) or 50%.
There are a total of 6 odd numbers: 1, 3, 5, 7, 9, and 11.
To find the probability of Bryson choosing an odd number, use the formula for probability:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
\]
In this case, the number of favorable outcomes (choosing an odd number) is 6, and the total number of outcomes (total cards) is 12.
\[
\text{Probability of choosing an odd number} = \frac{6}{12} = \frac{1}{2}
\]
Therefore, the probability that Bryson will choose an odd number is \(\frac{1}{2}\) or 50%.